2x^4-15x^2-8=0

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Solution for 2x^4-15x^2-8=0 equation:


Simplifying
2x4 + -15x2 + -8 = 0

Reorder the terms:
-8 + -15x2 + 2x4 = 0

Solving
-8 + -15x2 + 2x4 = 0

Solving for variable 'x'.

Factor a trinomial.
(-1 + -2x2)(8 + -1x2) = 0

Subproblem 1

Set the factor '(-1 + -2x2)' equal to zero and attempt to solve: Simplifying -1 + -2x2 = 0 Solving -1 + -2x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -2x2 = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -2x2 = 0 + 1 -2x2 = 0 + 1 Combine like terms: 0 + 1 = 1 -2x2 = 1 Divide each side by '-2'. x2 = -0.5 Simplifying x2 = -0.5 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(8 + -1x2)' equal to zero and attempt to solve: Simplifying 8 + -1x2 = 0 Solving 8 + -1x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1x2 = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1x2 = 0 + -8 -1x2 = 0 + -8 Combine like terms: 0 + -8 = -8 -1x2 = -8 Divide each side by '-1'. x2 = 8 Simplifying x2 = 8 Take the square root of each side: x = {-2.828427125, 2.828427125}

Solution

x = {-2.828427125, 2.828427125}

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